Question

The course for a local triathlon has the shape of a right triangle. The legs of the triangle consist of a 4-mile swim and a 11 mile run. The hypotunuse of the triangle is the biking portion of the event. How far is the biking part of the triathlon?

Answer 1

Answer:

The biking part of the triathlon is 11.70 miles away.

Step-by-step explanation:

From the right angle Δ ABC

$AC^{2} = AB^{2} + BC^{2}$

Since AB = 4 mile

& BC = 11 miles

⇒ $AC^{2} = 11^{2} + 4^{2}$

⇒ $AC^{2}$ = 121 + 16

⇒ $AC^{2}$ = 137

⇒ AC = $\sqrt{137}$

⇒ AC = 11.70 miles

Thus the biking part of the triathlon is 11.70 miles away.