All categories

3 years ago

Help ASAP!!! Please and thank you

Mathematics

1 answer:

Neporo4naja [7]3 years ago

7 0

‘| |’ means modulus.
It’s turns the internal value positive.
We get a negative answer while finding the area of a triangle because there points in the quadrant other than the 1st quandrant i.e where all values are positive
Area of a triangle can never be negative, so we use modulus

You might be interested in

y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence

sukhopar [10]

Let

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots$

Differentiating twice gives

$\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots$

$\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n$

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

$\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0$

$\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0$

Then the coefficients in the power series solution are governed by the recurrence relation,

$\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}$

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

$k=0 \implies n=0 \implies a_0 = a_0$

$k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}$

$k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}$

$k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}$

It should be easy enough to see that

$a_{n=2k} = \dfrac{a_0}{(2k)!}$

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

$k = 0 \implies n=1 \implies a_1 = a_1$

$k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}$

$k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}$

$k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}$

so that

$a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}$

So, the overall series solution is

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)$

$\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}$

4 0

2 years ago

Someone's quiz grades in the second quarter. (78, 90, 95, 84, 80, 82, 87, 98, 72 ) Find the Median.

jeka57 [31]

Step-by-step explanation:

I believe the answer is 80 cuz it's in the middle

7 0

2 years ago

Read 2 more answers

What is the unknown digit 5.723<572?<5.725

vovangra [49]

The unknown digit is 5.724

4 0

3 years ago

Read 2 more answers

Checking account A charged a monthly fee of $5 and a per-check fee of $0.25, and checking account B charged a monthly fee of $6

Genrish500 [490]

First we need to know both the formula of A and B.

The formula of A is
C = 5 + 0.25p
with C representing total cost and p representing the amount of checks.

The formula of B is
C = 6 + 0.15p
with C representing total cost and p representing the amount of checks.

To find the point where A and B cost the same, we solve the following equation:
5 + 0.25p = 6 + 0.15p

Collecting terms gives us
-1 = -0.1p

Now we have to divide by -0.1 and we get.
10 = p
p = 10

So our answer: after 10 checks both accounts cost the same amount of money. Answer A.

7 0

2 years ago

Which set of number is only made up of integers?

Rashid [163]

Answer:

It is D (-23, -7, 5, 9, 190)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers