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Tatiana [17]
4 years ago
6

I don't know how to solve

Mathematics
1 answer:
Trava [24]4 years ago
8 0
The answer would be 29* because the two measurements should be equal to 180*. So the value of one angle plus the value of the other angle equal 180. You gather all like values in the equation, then leave the x by it self by dividing. After you have the final x value, you substitute x to the initial values to give the final angle results.

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Solve the system of equations 2x - 2y = - 14 and 2x + 6y = - 6 by combining the equations.
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sorrryy I don't know how to delete this so...

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If you are 6 foot tall and cast a shadow of 4 feet. How tall are you.
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You are 10ft tall if you have a shadow of 4ft
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Use the​ slope-intercept form to graph the equation y=5/4x-1
schepotkina [342]

Answer:

m = 5/4

(0,-1),(4/5,0)

Join the dots to obtain the graph!

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3 years ago
Please help, will mark brainliest
dem82 [27]

Answer:

34.6= b

Step-by-step explanation:

a^2 + b^2 =c^2

13^2+b^2= 37^2

169+b^2= 1369

-169            -169

b^2 = 1200

\sqrt{b} = \sqrt{1200\\

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3 years ago
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A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
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