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Olenka [21]
2 years ago
11

1. What is the slope of a line parallel to the line whose equation is y = 2/5x - 3?

Mathematics
1 answer:
yuradex [85]2 years ago
3 0
It should be equivalent to 2/5 as that if the slope
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Can someone explain how to graph this? I know how to graph it in the y= format. So can someone explain how to get these equation
artcher [175]

Answer:

hope this helps.

Step-by-step explanation:

You don't really need to get them in the y format.

make a table and plug some numbers in and graph those points

use a ruler to connect the dots.

y = -3 is a horizontal line

8 0
3 years ago
Find the second derivative y= x^2lnx
Dimas [21]
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx

now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
         1+2+2lnx
         3+2lnx is the answer


3 0
3 years ago
.<br> 2. Find the volume of the right cone.<br> 4 cm<br> 3 cm
Ainat [17]

Answer:

i dont get it please alaborate

Step-by-step explanation:

4 0
2 years ago
2x + 3y = 3 and x + 6y = -3
jekas [21]

Answer:

Step-by-step explanation:

Multiplying x+6y=-3 with 2 so its equal to first eqn,

Eliminating,

2x + 3y = 3        (1)

2x +12y = -6       (2)                  (because subtracting)

------------------

      -9y =9

     ∴y=-1

eq. y in 1

2x -3=3

2x=3+3

x=6/2

=3

Pls mark me brainliest

4 0
2 years ago
6) find HJ<br> 8)find IK
Anastasy [175]

Answer:

HJ = 17

IK = 30

Step-by-step explanation:

to find HI :

GH : 2

HI : ?

IJ : 12

GI : 7

HI = GI - GH

HI = 7- 2

HI = 5

HI + IJ = HJ

5 + 12 = HJ

17 = HJ

To find IK

IJ = ?

JK = 12

KL = ?

IL = 49

JL = 31

To find IK we need to find KL and IJ

KL = JL - JK

KL = 31 - 12

KL = 19

IJ = IL - (JK + KL)

IJ = 49 - 31

IJ = 18

IK = IJ + JK

IK = 18 + 12

IK = 30

4 0
3 years ago
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