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3 years ago

PLSS HELP ASAP ILL GIVE BRAINLKEST

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

The quotient of a number and four increased by three.

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Help me pls !! i don’t understand

olganol [36]

C divided by 9 = D!.........

5 0

3 years ago

G(x) = 3x2 + 14x – 5?

Alla [95]

Answer:

x= $-\frac{1}{14}$

Step-by-step explanation:

im going to assume the 3x2 mean 3 times 2

3 0

3 years ago

Read 2 more answers

A company, Second Brain, produces calculators. It costs them $750 operating cost per week plus $6 per case of calculators manufa

musickatia [10]

Operating cost = $750

Working hours per day = 10

Total working hours per week = 70

Number of cases produced per hour = 50

So, number of cases produced in a week = 50 × 70 = 3500

If x is the manufacturing cost per hour, then

Manufacturing cost for 3500 cases produced in a week = 3500x.

Total cost = Operating cost + Manufacturing cost

Hence, total cost C(x) = 750 + 3500x.

Number of cases produced in 1 hour = 50

Number of cases produced in t hours = 50t.

Cost per case = $6.

Amount of cases produced in t hours x(t) = 6 × 50t = 300t.

C(x(t)) = C(300t) = 750 + 300t.

5 0

3 years ago

Read 2 more answers

A Boxer. needs to lose 3 1/2 kg in a month to be able to complete as a flyweight. In three weeks he lowers his weight from 55.5

Airida [17]

Answer: The boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

Step-by-step explanation:

Since we have given that

Quantity of weight a boxer needs to lose in a month is given by

$3\frac{1}{2}\ kg\\\\=\frac{7}{2}\ kg=3.5\ kg$

In 3 months, he lowers his weight from 55.5 kg to 53.8 kg.

So, Quantity of weight he lose in three months is given by

$55.5-53.8\\\\=1.7\ kg$

Number of kilograms the boxer lose in the final week to be able to compete as a flyweight is given by

$3.5-1.7\\\\=1.8\ kg$

Hence, the boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

4 0

3 years ago

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What are the coordinates of the point in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the r

boyakko [2]

Answer:

The coordinates of the point X:

(x, y) = (-1, -7)

Step-by-step explanation:

Let X be the point.

As the point X is in the directed line segment from (-2,-8) to (5,-1) into the ratio of 1 to 6

i.e.

$\left(x_1,\:y_1\right)\:=\:\left(-2,-8\right)$

$\left(x_2,\:y_2\right)=\left(5,-1\right)$

Rise = y₂ - y₁

$= -1 - (-8)$

$= -1 + 8$

$= 7$

Run = x₂ - x₁

$= 5 - (-2)$

$= 5 + 2$

$= 7$

1 : 6 ratio means the point X lies at

$\frac{1}{6+1}=\frac{1}{7}=14\%$

Thus,

rise for X $=\:7\:\times \:14\%=1$

run for X $=\:7\:\times \:14\%=1$

Thus, coordinates of X will be:

$x = -2 + 1 = -1$

$y = -8 + 1 = -7$

Therefore, we conclude that:

The coordinates of the point X:

(x, y) = (-1, -7)

8 0

3 years ago