Question

Arrange the parabolas with respect to the position of their vertices from left to right.

Answer 1

Answer:

6,7,1,3,2,4,5

Step-by-step explanation:

• Given points 1. y=f(4x+3) 2. y=f(x-3) 3. y=f(2x-1) 4. y=f(x/2 - 2) 5. y=f(x-7) 6. y=f(x+3)/3 7. y=f(x+2).
• If x is the position for vertex f(x) then k is:

             (1) f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4)  

             (2) x = k+3  

             (3) x = (k+1)/2 = (k/2)-(1/2)

             (4) x = 2(k+2) = 2k+4

             (5) x = k+7

             (6) x = k-3

             (7) x = k-2

For k = 0 the original positions will be:

            (1) -3/4

            (2) 3

            (3) -1/2

            (4) 4  

            (5) 7

            (6) -3

            (7) -2

So the order from left to right is 6,7,1,3,2,4,5.

Answer 2

Vertices - n+f(x)=

it means that y=n, right? so it is algebra and it makes sense.