Answer:
So the solution is -2<x<4 with it's graph is
O~~~~~~O
------(-2)--------(4)-----------
Step-by-step explanation:
The intersection symbol means it has to be included in both sets.
We have that x<4 and x>-2.
If we graph this, where do we see both shadings:
~~~~~~~~~~~~~~~0 x<4
O~~~~~~~~~~~~~~~~~ x>-2
-------(-2)-------------(4)------------
Both shadings happen between -2 and 4 (and not outside that area).
So the solution is -2<x<4
It's graph is
O~~~~~~O
------(-2)--------(4)-----------
Disclaimer:
I didn't see any equal signs in your problem.
You know the or the so we didn't have any closed dots.
Answer:
Step-by-step explanation:
<u>Use the law of cosines to find the side AB:</u>
<u>Use the Heron's area formula next:</u>
- , where s- semi perimeter
- s = 1/2[x + x + 3 + ) = 1/2 (2x + 3 + )
- s - a = 1/2 (2x + 3 + - 2x - 6) = 1/2 ( - 3)
- s - b = 1/2 (2x + 3 + - 2x) = 1/2 ( + 3)
- s - c = 1/2 (2x + 3 + - 2) = 1/2 (2x + 3 - )
<u>Now</u>
- (s - a)(s - b) = 1/4 [(x²+3x+9) - 9] = 1/4 (x² + 3x)
- s(s - c) = 1/4 [(2x + 3)² - (x² + 3x + 9)] = 1/4 (3x²+ 9x) = 3/4(x² + 3x)
<u>Next</u>
- A² = 3/16(x² + 3x)(x² + 3x)
- 300 = 3/16(x² + 3x)²
- 1600 = (x² + 3x)²
- x² + 3x = 40
<u>Substitute this into the first equation:</u>
The answer would either be y-6 = -3(x+2) or y = -3x
5-x>2
subtract 5 from both sides to get -x>-3
divide by -1 and flip the sign x<3
any number less than three satisfies the given equation
Y=5/3x-9 is the correct answer in slope intercept form :). The point slope form is y+14=5/3times(x+3)