Answer:
In the F1 generation
RR = 0%
Rr = 50% (or 0.5)
rr = 50% (or 0.5)
Explanation:
A pink flowering plant has the genotype Rr. It is heterozygous for the allele. The alleles for this gene appears to show incomplete dominance, as the heterozygous phenotype is a blend of the two homozygous genotypes.
A white flowering plant has the genotype rr. It is homozyogous for the white allele
A punnet square of the cross is shown.
The resulting punnet square shows that only Rr and rr genotypes are possible, at a ratio of 50:50 (or 1:1). Therefore, the genotype frequency of Rr is 50%, and rr is 50% in the F1 generation. This can also be written as 0.5. It is not possible to get a red plant, as the genotype RR can not come from this cross
The answer is dominant.
A monohybrid cross involves organisms that are heterozygous for only one character. In autosomal dominant traits, the phenotype is present if both copies of the dominant allele (A) are present (homozygous individuals AA) or only one copy of the dominant allele is present (heterozygous individuals Aa). <u>Thus, t</u><span><u>he characteristic that results from a monohybrid cross is the dominant trait.</u></span>
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A. Kinetic energy is the energy of motion. B,C,D all describe situations where there is not movement.
