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2 years ago

What is the gcf to 36 k and 144km

Mathematics

2 answers:

Oliga [24]2 years ago

8 0

The gcf of 36k and 144km would be 36

leonid [27]2 years ago

7 0

The GCF is 36 since 36 can go into 144 (:
x

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10% as a decimal (a value between 0 and 1) is 0.1

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3 years ago

5x+y=-10 4x-7y=-8 Substition Method (Show it step by step please!)

Fynjy0 [20]

$\left\{\begin{array}{ccc}5x+y=-10&|\text{subtract 5x from both sides}\\4x-7y=-8\end{array}\right\\\left\{\begin{array}{ccc}y=-5x-10&|\text{substitute to the second equation}\\4x-7y=-8\end{array}\right\\\\4x-7(-5x-10)=-8\qquad\text{use distributive property}\\\\4x+(-7)(-5x)+(-7)(-10)=-8\\\\4x+35x+70=-8\qquad\text{subtract 70 from both sides}\\\\39x=-78\qquad\text{divide both sides by 39}\\\\\boxed{x=-2}\\\\\text{Put the value of x to the first equation}\\\\y=-5(-2)-10\\\\y=10-10\\\\\boxed{y=0}$

$Answer:\ \boxed{x=-2\ and\ y=0}$

3 0

3 years ago

Read 2 more answers

Can anybody help me please

Alexxandr [17]

Step-by-step explanation:

I think you are clear. You can follow me to get more answers. Thanks.

5 0

2 years ago

A rectangular pyramid measures three feet by four feet at the base, and has a height of seven feet. Find its volume. A. 21 ft3 B

sweet-ann [11.9K]

Answer:

C. 28 ft³

Step-by-step explanation:

The general formula for the volume of a pyramid:

V = $\frac{1}{3}Bh$ , where B = the area of the base and h = height of the pyramid

Since the base is a rectangle, we can find area using the formula:

A = l x w or A = 3 x 4 = 12 ft²

Using B = 12 and h = 7:

V = $\frac{(12)(7)}{3}$

V = 28 ft³

3 0

2 years ago

Find the distance between the two points in simplest radical form.<br> (-1,9) and (4, -3)

jolli1 [7]

Answer:

GIVEN BY POINTS :-

( -1, 9) , ( 4 , -3)

Here ,

$\bullet \: \: x _{1} = - 1 \\ \bullet \: \: x _{2} = 4 \\ \bullet \: \: y _{1} = 9 \\ \bullet \: \: y _{2} = - 3 \\$

Using Distance formula :

$= > \sf d = \sqrt{( {x _{2} - x _{1}) }^{2} + {( {y _{2} - y _{1}) }^{2} } } \\ \\ = > \sf d = \sqrt{ ({ 4 + 1)}^{2} + { ( - 3 - 9)}^{2} } \\ \\ = > \sf d = \sqrt{ {5}^{2} + {( - 12)}^{2} } \\ \\ = > \sf d = \sqrt{25 + 144} \\ \\ = > \sf d = \sqrt{169} \\ \\ = > \boxed{ \sf{ d = 13\:units }}\\$

8 0

3 years ago