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Lapatulllka [165]
3 years ago
14

Wizer.me Simplify the following problem: (30 – 3) = 3​

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

-10/1 is simplified for 30/3

hope this helps

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Read the following lines from the poem “At the Tourist Centre in Boston.”
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"Irate" is the word among the choices given in the question that <span>best describes the speaker’s tone. The correct option among all the options that are given in the question is the third option or the penultimate option or option "C". I hope that this is the answer that has come to your desired help.</span>
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Joey and Emily’s teacher gave them each a triangle
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What does that mean if you don’t give us a hint?
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4 years ago
Find the slope of the line passing through the points (7, -1) and (2, -8).
Ugo [173]

Answer:

\frac{4}{5}

Step-by-step explanation:

We have to use the slope formula: m = slope

(x1, y1) = coordinates of the first point in the line

(x2, y2) = coordinates of the second point in the line

Here, we'll plug into our given points to give; \frac{7--1}{2--8}

Solving this, we get, \frac{8}{10}, but we're not done, as this fraction can be reduced.

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8 0
3 years ago
Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall
harina [27]

Answer :

  • 4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

{\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}

\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}

\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}

Therefore,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: the  \: wall = length \times breadth \times height}}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: the  \: wall = 1000 \times 24 \times 400 \:  {cm}^{3} }}}

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: each  \: brick = length \times breadth \times height}}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: each  \: brick = 24 \times 12 \times 8 \:  {cm}^{3} }}}

So,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: bricks  \: required =  \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: bricks  \: required =  \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: bricks  \: required =   \bf \: 4166.6} }}

Therefore,

  • <u>The wall requires 4167 bricks. </u>

6 0
2 years ago
How can you use 4x7 to find 8x7?
max2010maxim [7]
4 x 7 is 28, and 8 x 7 is 56. You can use 4 x 7 to find 8 x 7 by multiplying that first and doubling that quotient.

Half of 56 is 28, therefore doubling that allows us to find the quotient of 8 x 7.
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