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2 years ago

Solve 2y-3 = 4y + 6. y=?

Mathematics

2 answers:

valentinak56 [21]2 years ago

5 0

y= 3/8 OR 0.375

Step-by-step explanation:

yes

Diano4ka-milaya [45]2 years ago

5 0

Answer:

y = - 4.5

Step-by-step explanation:

2y - 3 = 4y + 6 ( subtract 4y from both sides )

- 2y - 3 = 6 ( add 3 to both sides )

- 2y = 9 ( divide both sides by - 2 )

y = - 4.5

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One number exceeds another by 24. The sum of the numbers is 58. What are the numbers?

Anna35 [415]

X + x + 24 = 58
x = (58-24)/2=17
the first number is 17 and the second number is the sum of 17 and 28. Finding it has been left as an exercise for the reader.

3 0

3 years ago

I will like to know how to solve this

Alexxandr [17]

This is a linear equation in x.

So you need to group like terms

$1 + 4x = - 5 + 7x$
Let us group the x terms on the Right Hand Side of the equation and the constant terms on the Left Hand Side.

$1 + 5 = 7x - 4x$
We can now simplify

$6 = 3x$
Now let us divide both sides by 3.

$\frac{6}{3} = \frac{3x}{3}$

This implies that

$2 = x$
or

$x = 2$
Let us our answer

$1 + 4(2) = - 5 + 7(2)$

$1 + 8 = - 5 + 14$
$9 = 9$
Good we are right

5 0

3 years ago

Read 2 more answers

A rectangle has a length of 19 in and a height of 11 in. Another rectangle has a length of 95

scoundrel [369]

Answer:

Option D. No,they are not similar because their side lengths are not proportional.

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem If the rectangles are similar

then

The ratio of its corresponding lengths must be equal to the ratio of its corresponding heights

Verify

$\frac{95}{19}=\frac{6.5}{11}\\\\95*11=19*6.5\\\\1,045\neq123.5$

therefore

The rectangles are not similar because their side lengths are not proportional.

4 0

3 years ago

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ale4655 [162]

Answer:

hereee (:

Step-by-step explanation:

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3 years ago

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The distance between consecutive bases in Major League Baseball is 90 feet. Find the distance from home plate to second base.

sashaice [31]

Assuming the bases are laid out in a square, then we can use the Pythagorean Theorem to find the distance from home plate to second base.

This distance is exactly the length of the hypotenuse of the right triangle that forms when you split the square along the diagonal. Let this distance be x

Each of the legs are 90 ft, so a = 90 and b = 90. The hypotenuse is c = x for now.

a^2 + b^2 = c^2
90^2 + 90^2 = x^2
8100 + 8100 = x^2
16200 = x^2
x^2 = 16200
sqrt(x^2) = sqrt(16200) ... apply the square root to both sides
x = 127.2792206
x = 127.3 .... round to the nearest tenth (one decimal place)

The final answer is 127.3 feet

5 0

3 years ago