So
x=earned
x>200
they paid their parrents 28 for supplies (this assumes that they paied 28 altogether and not 28 each)
so subtract 28 from pay
new pay=y
y>200-28
y>172
divided it among themselves (3)
172/3=57 and 1/3=57.33
they each earned more that $57.33
Answer:
0, 1, 2, 3, 4, 5
Step-by-step explanation:
When you divide a natural number by 6, the remainders you can get are 0, 1, 2, 3, 4, and 5. Hope this helps!
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
