From the law of sines, we have
![l = h\sin(\theta) = h\cos(\alpha)](https://tex.z-dn.net/?f=%20l%20%3D%20h%5Csin%28%5Ctheta%29%20%3D%20h%5Ccos%28%5Calpha%29)
where
is the leg we're interested in,
is the hypothenuse,
is the angle opposite to
, and
is the angle between
and
.
So, in the first case, we can use
![x = 15\sin(35) \approx 8.6](https://tex.z-dn.net/?f=%20x%20%3D%2015%5Csin%2835%29%20%5Capprox%208.6%20)
And in the second excercise, we use
![x = 11\cos(44) \approx 7.6](https://tex.z-dn.net/?f=%20x%20%3D%2011%5Ccos%2844%29%20%5Capprox%207.6%20)
Answer:
a) x = 62
b) x = 33
Step-by-step explanation:
Hi there!
a) Let´s write the equation:
√(2x-3) = 11
Square both sides
2x - 3 = 121
add 3 to both sides of the equation
2x = 124
divide by 2 both sides
x = 62
Let´s check:
√(2x-3) = 11
x = 62
√(2(62)-3) = 11
√(124-3) = 11
√121 = 11
11 = 11
x = 62 satisfies the equation
b) Let´s write the equation:
∛(6 - x) = -3
Cube both sides
6 - x = -27
subtract 6 to both sides
-x = -27 - 6
-x = -33
divide by -1 both sides
x = 33
Now, let´s check the result:
∛(6 - x) = -3
x = 33
∛(6 - 33) = -3
∛(-27) = -3
-3 = -3
x = 33 satisfies the equation
Answer:
Caleb keeps 65% of his mask collection on the wall.
<span>In order to determine the total number of errors that were made by the bar code scanner, we first have to calculate how many total scans were made. Because there were six items scanned 1,000 times each, there were 6,000 total scans made. Next, we have to add up the total number of errors made by each item (36+14+21+39+11+2). As a result, there were a total of 123 errors made during the 6,000 scans.</span>
18). 16:80 is the ratio but in simplest form is; 5:0
19). 36:54 is the ratio but in simplest form is; 2:3
20). 12:24 is the ratio but in simplest form is; 1:2
hope that helps:D