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expeople1 [14]
3 years ago
14

What is the unit rate for hours per task

Mathematics
1 answer:
timama [110]3 years ago
4 0
What is the task and how many hours does it take?
You might be interested in
Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 =
Svetradugi [14.3K]

Answer:

\lambda=8,\ \lambda=-5

Step-by-step explanation:

<u>Eigenvalues of a Matrix</u>

Given a matrix A, the eigenvalues of A, called \lambda are scalars who comply with the relation:

det(A-\lambda I)=0

Where I is the identity matrix

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix is given as

A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]

Set up the equation to solve

det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0

Expanding the determinant

det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0

(3-\lambda)(-\lambda)-40=0

Operating Rearranging

\lambda^2-3\lambda-40=0

Factoring

(\lambda-8)(\lambda+5)=0

Solving, we have the eigenvalues

\boxed{\lambda=8,\ \lambda=-5}

8 0
3 years ago
Find the 8th term of the G.P 9,3,1,​
son4ous [18]

Answer:

a=9 , d=6 n=8

a+(n-1)d = an

9+(8-1)6 = an

9+7×6 = an

9+42 = an

51 = an

5 0
3 years ago
Please help no link as answers
Katarina [22]

Step-by-step explanation:

You can imagine this figure as a rectangle and cube

If you want volume of this irregular figure than you have to do it like this:

V(figure)= V(rectangle)+ V(cube)

V(figure)= a*b*c+ a³

V(figure)= 4*3*(I don't see dimension on the left)+ 3³

V(figure)=12*(I don't see dimension on the left)+ 27

And only you have to to do is to set this dimension which I can't see.

6 0
3 years ago
I will mark you
Nana76 [90]

Answer:

Yes, because the x's do not have more than one y.

Step-by-step explanation:

x      y

0      0

5       10

6       12

10     20

(That's meant to be a table). Looking at the x and y table values, you can see that none of the x's have two y's. So, this relation is a function.

7 0
3 years ago
If g(x)= square root of 3-5x, find the domain of g'(x).
BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0
3 years ago
Read 2 more answers
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