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Aleks04 [339]
3 years ago
14

Find the distance between the points (13,5) and (10,1)

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0
The distance is (3,4)

Simply subtract the x and y functions.

13 - 10 = 3 

5 - 1 = 4 

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Solve this system of equations- x=2y-8 and 4x+y=13
rjkz [21]
(2,5)
thats what i got

8 0
3 years ago
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Help Pls I need the answer to t<br><br><img src="https://tex.z-dn.net/?f=0%3D-16t%5E2%2B704t" id="TexFormula1" title="0=-16t^2+7
Xelga [282]

Answer:

t=0 or t=44

Step-by-step explanation:

There are a few methods to do this, the most obvious being the use of the quadratic formula.

However, a quick check with a calculator or even your mind will reveal that 704 is divisible by 16. Thus we can solve this through factoring.

-16t(t-44)=0

Using the zero factor principle:

-16t=0 and so t=0

t-44=0 and so t=44

And thus we get the solution.

7 0
3 years ago
System of Equations <br> Need help<br> Trig
Yanka [14]

Looks like the system is

\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}

We can eliminate y by taking

(3x+2y+5z)-2(-2x+y+6z)=16-2(1)

\implies3x+2y+5z+4x-2y-12z=16-2

\implies7x-7z=14

\implies x-z=2

so that z=x-2, and

(7x+3y-4z)-3(-2x+y+6z)=11-3(1)

\implies7x+3y-4z+6x-3y-18z=11-3

\implies13x-22z=8

Substitute z=x-2 into this last equation and solve for x:

13x-22(x-2)=8

\implies13x-22x+44=8

\implies-9x=-36

\implies x=4

Then

z=x-2

\implies z=4-2

\implies z=2

Plug these values into any one of the original equation to solve for y:

-2x+y+6z=1

\implies-2(4)+y+6(2)=1

\implies-8+y+12=1

\implies y=-3

Hence the solution is x = 4, y = -3, and z = 2.

6 0
3 years ago
Complete diagram fill in squares
mojhsa [17]
Area A Output: 2, 4, 6, 8
Perimeter P Output: 6, 8, 10, 12

Explanation: Just replace the x with the inputs and then solve.
6 0
2 years ago
Read 2 more answers
Y-4=0 in standard form
wolverine [178]
Standard form : Ax + By = C

y - 4 = 0
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so in standard form, ur equation is : 0x + y = 4
7 0
2 years ago
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