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2 years ago

Find the distance between the points (13,5) and (10,1)

Mathematics

1 answer:

ElenaW [278]2 years ago

8 0

The distance is (3,4)

Simply subtract the x and y functions.

13 - 10 = 3

5 - 1 = 4

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The average value of the function y = x² – 1 on [0, 12] is

shusha [124]

Answer:

47.

Step-by-step explanation:

1) the rule:

$f_{avr}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx ,$

where a;b are 0 and 12, f(x)=x²-1.

2) according to the rule above:

$f_{avr}=\frac{1}{12-0} \int\limits^{12}_0 {(x^2-1)} \, dx=\frac{1}{12}(\frac{x^3}{3}-x)|^{12}_0=48-1=47.$

3 0

1 year ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

Lois and Clark own a company that sells wagons. The amount they pay each of their sales employees (in dollars) is given by the e

ira [324]

You can replace the h and w with 6 and 3 in the expression. Then the expression is 12*6+30*3=162 dollars. So the amount paid to this employee is 162 dollars.

4 0

2 years ago

Complete the equation for the line

Serggg [28]

Answer:

Yes

Step-by-step explanation:

4 0

2 years ago

Which of the following is equal to the expression listed below?

Sliva [168]

Answer:

C. 9(3+2)

Step-by-step explanation:

9*3 = 27 and 9*2 = 18 then add which gives you 45

Or do it this way

9(3+2) = 9(5) = 45

Hope this helps!

3 0

2 years ago

Read 2 more answers