You'd use the equation y2-y1/x2-x1
0-(-3)/-7-5 = 3/-12 = -1/4
So -1/4 would be the slope
m= -1/4
Answer: 
Step-by-step explanation:
use the equation 
we know the slope, y, and x, so plug in
(2x + 8) (x+2) is what I got
H(x) = 4x² - 8x - 60
0 = 4x² - 8x - 60
0 = 4(x²) - 4(2x) - 4(15)
0 = 4(x² - 2x - 15)
4 4
0 = x² - 2x - 15
0 = x² - 5x + 3x - 15
0 = x(x) - x(5) + 3(x) - 3(5)
0 = x(x - 5) + 3(x - 5)
0 = (x + 3)(x - 5)
0 = x + 3 or 0 = x - 5
- 3 - 3 + 5 + 5
3 = x or 5 = x
Answer:
a) Sinusoidal functions are y = a sin [b(x-h)] + k (or)
y = a cos [b(x-h)] + k
Where a is amplitude a= (max-min)/2=(16-2)/2=7
period p= 2π/b
b=2π/30
Horizontal transformation to 10 units right h=10
k= (max+min)/2=(16+2)/2=9
h = 7 cos [π/15(t-10)]+ 9
b) t=10min=600 sec
substitue in the above equation
h=5.5m
