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2 years ago

I PROMISE BRAINLIST; 5-STARS; THANKS!! IT'S VERY SIMPLE; BELIEVE ME

Mathematics

2 answers:

goldfiish [28.3K]2 years ago

4 0

Alright! Let me draw one out for you! c: Here you go! I hope this helps! It took me a while ~w~

Don't juge my handwriting It took a while T~T I couldn't put in the whole picture but the pattern was.

Turkey - Japan : 1.7

UK - Finland: 2.8

Austria - Germany : 3.3

Spain - Sweden : 4.4

Denmark- Switzerland : 5

France - Norway : 5.5

Canada - U.S : 7.5

Hope this helps!~

lidiya [134]2 years ago

3 0

Answer:

Classes  Frecuency 

0.0 - 0.9 1

1.0 - 1.9 5

2.0 - 2.9 5

3.0 - 3.9 2

4.0 - 4.9 1

Step-by-step explanation:

The scale of equal intervals is characterized by a common and constant unit of measure that assigns a number equal to the number of units equivalent to that of the magnitude of the observed element. It is important to note that the zero point in the scales of equal intervals is arbitrary, and does not reflect at any moment absence of the magnitude that we are measuring.

This scale, besides having the characteristics of the ordinal scale, we find that the assignment of the numbers to the elements is so precise that we can determine the magnitude of the intervals (distance) between all the elements of the scale. Undoubtedly, we can say that the scale of intervals is the first truly quantitative scale and the characters that have this scale can be calculated all the statistical measures except the coefficient of variation.

The data is classified into classes divided into equivalent intervals. The range is then divided by the number of classes, which gives the common difference.

1. Define the number of equals intervals .

Each interval increase 0.9.

2. Make a frecuency table.

We select each country which is within the range of each class and we add in the frecuency column the countries that fall within the range of that class.

Classes  Frecuency 

0.0 - 0.9 1

1.0 - 1.9 5

2.0 - 2.9 5

3.0 - 3.9 2

4.0 - 4.9 1

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Type the correct answer in each box. Use numerals instead of words. Any non-integer answers in this problem should be entered as

ladessa [460]

Answer:

The interquartile range of the data set is 5

The mean absolute deviation of the data set is 3.6

Step-by-step explanation:

* Lets explain how to find the interquartile range and the mean absolute

deviation (MAD)

- The steps to find the interquartile range is:

1- Arrange the values from the smallest to the largest

∴ The values are 5 , 6 , 10 , 11 , 12 , 13 , 14 , 15 , 18 , 20

2- Find the median

- The median is the middle value after arrange them

* If there are two values in the middle take their average

∵ The values are 10 then the 5th and the 6th are the values

∵ The 5th is 12 and the 6th is 13

∴ The median = $\frac{12+13}{2}=12.5$

∴ The median is 12.5

3- Calculate the median of the lower quartile

- The lower quartile is the median of the first half data values

∵ There are 10 values

∴ The first half is the first five values

∴ The first half values are 5 , 6 , 10 , 11 , 12

∵ The middle value is 10

∴ The median of lower quartile = 10

- Similar find the median of the upper quartile

- The upper quartile is the median of the second half data values

∵ There are 10 numbers

∴ The second half is the last five values

∴ The second half values are 13 , 14 , 15 , 18 , 20

∵ The middle value is 15

∴ The median of upper quartile = 15

4- The interquartile range (IQR) is the difference between the upper

and the lower medians

∴ The interquartile range = 15 - 10 = 5

* The interquartile range of the data set is 5

* Lets talk about the mean absolute deviation

- Mean absolute deviation (MAD) of a data set is the average distance

between each data value and the mean

- To find the mean absolute deviation of the data, start by finding

the mean of the data set.

1- Find the sum of the data values, and divide the sum by the

number of data values.

∵ The data set is 5 , 6 , 10 , 11 , 12 , 13 , 14 , 15 , 18 , 20

∵ Its sum = 5 + 6 + 10 + 11 + 12 + 13 + 14 + 15 + 18 + 20 = 124

∵ The mean = the sum of the data values/the number of the data

∵ The set has 10 numbers

∴ The mean = 124/10 = 12.4

2- Find the absolute value of the difference between each data value

and the mean ⇒ |data value – mean|

# I5 - 12.4I = 7.4

# I6 - 12.4I = 6.4

# I10 - 12.4I = 2.4

# I11 - 12.4I = 1.4

# I12 - 12.4I = 0.4

# I13 - 12.4I = 0.6

# I14 - 12.4I = 1.6

# I15 - 12.4I = 2.6

# I18 - 12.4I = 5.6

# I20 - 12.4I = 7.6

3- Find the sum of the absolute values of the differences.

∵ Their sum = 7.4 + 6.4 + 2.4 + 1.4 + 0.4 + 0.6 + 1.6 + 2.6 + 5.6 + 7.6

∴ Their sum = 36

4- Divide the sum of the absolute values of the differences by the

number of data values to find MAD

∴ MAD = The sum of the absolute values/number of the values

∵ The sum = 36

∵ The data set has 10 values

∴ MAD = 36/10 = 3.6

* The mean absolute deviation of the data set is 3.6

6 0

2 years ago

What is the range of the function y=e^4x? y<0 y>0 y<4 y>4

Oliga [24]

We have been given the function $y=e^{4x}$

We know that the range is set of y values for which the function is defined. Therefore, we will find the value for x and then observe the restriction is y's values.

$y=e^{4x}\\\ln y = \ln (e^{4x})\\\ln y =4x\\x=\frac{1}{4}\ln y$