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Ostrovityanka [42]
2 years ago
10

For question 3, use the Pythagorean Theorem.

Mathematics
1 answer:
Juliette [100K]2 years ago
3 0

Step-by-step explanation:

can't really use the Pythagorean because you don't know this is a right triangle.

use the fact that they are similar

so

3/6 = x/12 where x is FE

cross multiply

6x = 36 therefore FE = 6

then 6/12 = y/9 where y is FD

cross multiply

12y = 54 = 54/12 therefore FD = 4.5

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The lines below are perpendicular. If the green line has a slope of 3/4 what is the slope of the red line? Enter your answer as
krek1111 [17]

Answer:

-4/3

Step-by-step explanation:

m1m2=-1

so 3/4*X= -1

3X=-4

x= -4/3

5 0
2 years ago
Determine if this data is an example
tankabanditka [31]

Answer:

Step-by-step explanation:

it is not a function because -2 has two y values

6 0
3 years ago
Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

6 0
3 years ago
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mel-nik [20]

Answer:

One- half

Step-by-step explanation:

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where d is the uniform density.

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where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

7 0
2 years ago
Pythagorean theorem (picture provided)
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<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

8 0
3 years ago
Read 2 more answers
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