There are 4! = 24 poosible permutations of the four letters. Let the letters be A, B, C and D. Two permutations will have only letter A in the correct envelope, two more permutations will have only letter B in the correct envelope, two more will have only letter C in the correct envelope and two more will have only letter D in the correct envelope. Therefore 8 out of the 24 possible permutations will have only one letter with the correct address. The required probability is 8/24 = 1/3.
Answer: T=1/2 Y + -5/2
Step-by-step explanation:
y=2t+5
2t+5 +-5= y +-5
2t=y-5 2t/2=y-5/2
t=1/2y+-5/2
= t=1/2y + -5/2
Answer:
B
Step-by-step explanation:
hope this helps with the work
