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damaskus [11]
3 years ago
13

How to solve? (x-3) (x+4) = x^2 + 4

Mathematics
2 answers:
julia-pushkina [17]3 years ago
8 0
First step, expand the left side (multiply together) (apply FOIL/distribution property)

2nd step, solve so that one side is zero, by adding/subtracting like terms

3rd step, solve for x
Tom [10]3 years ago
3 0
First, you have to multiply (x -3) times (x+4), which is x^2 + 4x - 3x -12 (because x times x +4 = x^2 + 4x, and -3 times x + 4 =  -3x -12). So now we have the equation x^2 + 4x - 3x -12 = x^2 + 4. Subtracting x^2 from both sides, we get 4x - 3x - 12 = 4. Now we subtract 4 from both sides and get 4x - 3x - 12 -4. If we add/subtract the like terms, we get x - 16. Adding 16 to both sides, we get x = 16. I hope this helps! :D
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3 years ago
11 chocolate bars cost 10 dollars
inna [77]

I'm not sure what you're trying to ask, but if you're trying to find the individual cost;

Solution: Cost of 1 candy bar is $0.91

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Hope This Helps!!!

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3 0
3 years ago
Please help!<br> Hard math.
Reil [10]

Answer:

the value of digit 3 in 156.32 =

3 x 0.1 = 0.3


The value of digit 3 in 13 =

3 x 1 = 3

3/0.3=10 times

The value of digit 3 in 13 is 10 ten times the value of digit 3 in 156.32

As long as the (digit in ones/single digit) of a number is equal to 3

The value of digit 3 of it is always 10 ten times the value of digit 3 in 156.32


5 0
3 years ago
Which of the following is a factor of 2xy + 8y − 8x − 32?
muminat
You could start by eliminating wrong answer(s):

(a) 5 is definitely not a factor of the given <span>2xy + 8y − 8x − 32,

(d) x^2 - 4x + 16 (not x2 - 4x + 16) is not a factor (it has no y terms)

On the other hand:

(b) 2 definitely divides evenly into </span>2xy + 8y − 8x − 32:  2(<span>xy + 4y − 4x − 16)

(c) x + 4 divides evenly into both xy + 4y and -(4x + 16):
                                           We get 2(x +4) [y - 4]</span>
4 0
4 years ago
What is the point that passes through the line Y-5=-3(x-4)
ioda
The point that passes through the line Y-5=-3(x-4) is (-4,7). You are very welcome.
5 0
3 years ago
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