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3 years ago

What is the algebraic expression for the following word phrase the quotient of 6 and z

Mathematics

2 answers:

BartSMP [9]3 years ago

7 0

Answer:

Step-by-step explanation:

Because of how its stated "the quotient of 6 and z."

STatiana [176]3 years ago

5 0

Answer:

i need ore detail

Step-by-step explanation:

need more detail

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Solve the following problem. Choose the correct answer. Fairhaven Church buys four tires for its van. Each tire is priced at $43

morpeh [17]

Answer:

169.65

Step-by-step explanation:

43.95x4= 175.80 175.80x3.5=6.15 175.80-6.15=169.65

5 0

3 years ago

naomi has earned $54 mowing lawns the past two days. she worked 2 1/2 hours yesterday and 4 1/4 hours today. if naomi is pains t

Vaselesa [24]

Answer:

Naomi charges $8 an hour to mow lawns

Step-by-step explanation:

first day // 2 1/2= 2.5 hrs

2nd day // 4 1/4= 4.25 hrs

2.5hrs + 4.25hrs = 54hrs // 6.75hrs = 54hrs

/6.75 /6.75

= 8hrs

Really hope this helps!

8 0

3 years ago

Which of the following is a ray shown in the drawing?

slavikrds [6]

Answer:

So to get the answer we need to find both of the rays. So first we need to find the end points for the horizontal one. That would be D and E for the horizontal. Those are points, do the same for the diagonal one. AC would be it. AC and DE would be the answer

4 0

3 years ago

What is the value of f? −18f−34−14f=11

Brrunno [24]

-18f - 34 - 14f = 11
-32f - 34 = 11
-32f = 45
f = -32/45
Simplify the fraction if needed!
Hope this helps, and please mark brainliest!

6 0

3 years ago

A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation of σ = 15. The researcher cal

laila [671]

Answer:

The mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with mean μ and standard deviation σ.

The z-scores are standardized form of the raw scores X. It is computed by subtracting the mean (μ) from the raw score x and dividing the result by the standard deviation (σ).

$z=\frac{x-\mu}{\sigma}$

These z-scores also follow a normal distribution.

The mean is:

$E(z)=E[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma}\times [E(x)-\mu] =\frac{1}{\sigma}\times [\mu-\mu]=0$

The standard deviation is:

$Var(z)=Var[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma^{2}}\times [Var(x)-Var(\mu)] =\frac{\sigma^{2}-0}{\sigma^{2}}=1\\SD(z)=\sqrt{Var(z)}=1$

Thus, the mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

8 0

3 years ago