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harina [27]
3 years ago
10

Two lengths of a triangle are shown.

Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0

Answer:

11 ft

Step-by-step explanation:

Given the two lengths of a triangle as

AB = 6ft

AC = 6ft

This is an isosceles triangle because only 2 sides are equal.

In an isosceles triangle, the sum of 2 (sides) lengths must be greater than the other length.

Therefore, let's assume the following:

i) AC + AB > BC

6 + 6 > BC

12 > BC (BC is less than 12)

BC < 12

ii) BC + AC > AB

BC + 6 > 6

BC > 6 - 6

BC > 0

Therefore the range of values for BC =

0 < BC < 12

Since BC must be bigger than one of the lengths and it must also be less than the sum of the 2 sides. The length of BC could be 11 because it is less than (6+6) 12 and greater than 6.

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Answer:

\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

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\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}

hope this helps

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