Question

Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y2 Is the student’s work correct?

Answer 1

No he's not correct

(3 – 6y2)(y2 + 2)  
= 3(y2) -6(y2)(y2)  - 6y2(2) + 3(2)
= 3y2 -6y4 - 12y2 + 6 
= -6y4 - 9y2 +6