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3 years ago

11x+5+-11x+29.........

Mathematics

2 answers:

Monica [59]3 years ago

7 0

Add like terms
11x and -11x cancel eachother out
5+29= 34
34 is the answer

Volgvan3 years ago

6 0

You can add like terms. Like terms are terms that have the same variables and the same exponent.

11x + 5 + -11x + 29 =

= 11x + -11x + 5 + 29

= 34

Answer: 34

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BabaBlast [244]

Answer:

1. 3 packs of daffodils and 4 packs of tulips

2. then you would have 24 of each

3. $2.29

4. $37.54

5. $34.61

6.$2.93 was saved

7. 3 tulips

8. 12 daffodils

9. 9 tulips

10. 12 daffodils and 15 tulips

theres 2 left. ill let someone else do it

Step-by-step explanation:

3. 4.50*4=18 5.75*3=17.25

18+17.25 -> 35.25*.065=2.29 rounded

4. 35.25+2.29=37.54

5. 35.25-2.75->32.50*.065=2.11 2.11+32.50=34.61

6. 37.54-34.61=2.93

7. 6:8 -> 3:4 ratio -> 3:4

8. 8+4=12

9. 6+3=9

10. 24-12=12 24-9=15

6 0

3 years ago

Which number is rational

Paul [167]

B is rational. B is the correct answer. B is rational.

7 0

3 years ago

Read 2 more answers

The numbers 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29 are written on separate cards, and the cards are placed on a table with th

SCORPION-xisa [38]

The probability of picking a card with an even number is $\frac{3}{10}$ .

<h3>What is probability?</h3>

Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

To find the probability of picking a card with an even number:

There are 10 cards on which numbers are written 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29.
These cards are placed on a table with the numbers facing down.
To find the probability of picking a card with an even number, first, we count all the even numbers written on the cards.
12, 14, and 18 out of 10 cards there are 3 even numbers written on the cards.
So, the probability of picking a card with an even number is $\frac{3}{10}$ .

Therefore, the probability of picking a card with an even number is $\frac{3}{10}$ .

Know more about probability here:

brainly.com/question/24756209

#SPJ4

COMPLETE QUESTION:

The numbers 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29 are written on separate cards, and the cards are placed on a table with the numbers facing down. The probability of picking a card with an even number is _____.

5 0

1 year ago

Can someone help me with this question

shtirl [24]

I believe its 5 shirts

4 0

3 years ago

For questions 13-15, Let Z1=2(cos(pi/5)+i Sin(pi/5)) And Z2=8(cos(7pi/6)+i Sin(7pi/6)). Calculate The Following Keeping Your Ans

weqwewe [10]

Answer:

Step-by-step explanation:

Given the following complex values Z₁=2(cos(π/5)+i Sin(πi/5)) And Z₂=8(cos(7π/6)+i Sin(7π/6)). We are to calculate the following complex numbers;

a) Z₁Z₂ = 2(cos(π/5)+i Sin(πi/5)) * 8(cos(7π/6)+i Sin(7π/6))

Z₁Z₂ = 18 {(cos(π/5)+i Sin(π/5))*(cos(7π/6)+i Sin(7π/6)) }

Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)+i²Sin(π/5)Sin(7π/6)) }

since i² = -1

Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)-Sin(π/5)Sin(7π/6)) }

Z₁Z₂ = 18{cos(π/5)cos(7π/6) -Sin(π/5)Sin(7π/6) + i(cos(π/5)sin(7π/6)+ Sin(π/5)cos(7π/6)) }

From trigonometry identity, cos(A+B) = cosAcosB - sinAsinB and sin(A+B) = sinAcosB + cosAsinB

The equation becomes

= 18{cos(π/5+7π/6) + isin(π/5+7π/6)) }

= 18{cos((6π+35π)/30) + isin(6π+35π)/30)) }

= 18{cos((41π)/30) + isin(41π)/30)) }

b) z2 value has already been given in polar form and it is equivalent to 8(cos(7pi/6)+i Sin(7pi/6))

c) for z1/z2 = 2(cos(pi/5)+i Sin(pi/5))/8(cos(7pi/6)+i Sin(7pi/6))

let A = pi/5 and B = 7pi/6

z1/z2 = 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B))

On rationalizing we will have;

= 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B)) * 8(cos(B)-i Sin(B))/8(cos(B)-i Sin(B))

= 16{cosAcosB-icosAsinB+isinAcosB-sinAsinB}/64{cos²B+sin²B}

= 16{cosAcosB-sinAsinB-i(cosAsinB-sinAcosB)}/64{cos²B+sin²B}

From trigonometry identity; cos²B+sin²B = 1

= 16{cos(A+ B)-i(sin(A+B)}/64

= 16{cos(pi/5+ 7pi/6)-i(sin(pi/5+7pi/6)}/64

= 16{ (cos 41π/30)-isin(41π/30)}/64

Z1/Z2 = (cos 41π/30)-isin(41π/30)/4

8 0

3 years ago