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adoni [48]
3 years ago
7

7)

Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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The product of 8 minus a number and seven equals 40 when decreased by 5
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7 football fields without the end zones
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3 years ago
Outcomes are equally likely of each is as likely to occur true or false
Brums [2.3K]

Answer:

true

Step-by-step explanation:

8 0
3 years ago
Solve the equation 12(-11x + 5) + 7 = 2 (x-9) - 451 algebraically. Answer as a reduced fraction only.
Pachacha [2.7K]

The value of x in the equation is 4.2.

<h3>How to calculate the value?</h3>

It should be noted that the equation given is:

12(-11x + 5) + 7 = 2 (x-9) - 451

This will be computed thus:

12(-11x + 5) + 7 = 2 (x-9) - 451

-132x + 60 + 7 = 2x - 28 - 451

Collect like terms

-132x - 2x = - 28 - 451 - 60 - 7

-130x = -546

Divide

x = 546/130

x = 4.2

The value of x in the equation is 4.2.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

6 0
2 years ago
A corporation must appoint a​ president, chief executive officer​ (CEO), chief operating officer​ (COO), and chief financial off
Zolol [24]

Answer:

(a) There are 32,760 different ways to appoint the officers.

(b) 3003 different ways can the committee be​ appointed.

(c) ​Probability of getting the five youngest of the qualified ​candidates is 0.00033.

Step-by-step explanation:

We are given that a corporation must appoint a​ president, chief executive officer​ (CEO), chief operating officer​ (COO), and chief financial officer​ (CFO). It must also appoint a planning committee with five different members.

There are 15 qualified​ candidates, and officers can also serve on the committee.

(a) The number of officers are 4, i.e; A president, chief executive officer​ (CEO), chief operating officer​ (COO), and chief financial officer​ (CFO).

There are 15 qualified candidates.

To find the number of ways to appoint the officers, we will use permutation because here the order of selecting the officer's matters.

So, the number of ways to appoint the officers = ^{15}\text{P}_4

            =  \frac{15!}{(15-4)!}              {\because  ^{n}\text{P}_r = \frac{n!}{(n-r)!} }

            =  \frac{15!}{11!}  =  32,760 ways

(b) The number of committee numbers to appoint include five members.

There are 15 qualified candidates.

To find the number of ways in which the committee can be​ appointed, we will use combination because here the order of selecting the members doesn't matter.

So, the number of ways to appoint the committee = ^{15}\text{C}_5

            =  \frac{15!}{5! \times (15-5)!}              {\because  ^{n}\text{C}_r = \frac{n!}{r! \times (n-r)!} }

            =  \frac{15!}{5! \times 10!}  =  3003 ways

(c) The probability of randomly selecting the committee members and getting the five youngest of the qualified​ candidates is given by;

Number of ways of selecting the committee = 3003

Selecting the five youngest of the qualified​ candidates = 1

So, the required probability =  \frac{1}{3003}

                                              =  <u>0.00033</u>

4 0
3 years ago
How to create a pattern with the rule n 3?
SCORPION-xisa [38]
If you copied the "n 3" part, it's very likely that your job was to create a pattern with either the rule n^3 or n*3.

In the case of the former, we can start with the initial number of 1 and increase by 1.
In that way, using the rule n^3 would create this pattern of numbers: 1, 8, 27, 64, and so on. Or stated in another way 1*1*1, 2*2*2, 3*3*3, 4*4*4 ...

In the case of the latter, we can start with the initial number of 1 and increase it by 1. 
In this way, using the rule of n*3 would create this pattern of numbers: 3, 6, 9, 12, 15, 18 and o son. Or stated in another way 1*3, 2*3, 3*3, 4*3, 5*3 ...
5 0
4 years ago
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