An airplane flew 900 miles and then flew back using the same route. On the return trip, the average speed was 100 miles/hour slo

Question

3 years ago

9

An airplane flew 900 miles and then flew back using the same route. On the return trip, the average speed was 100 miles/hour slo

wer than on the trip out because of some turbulence. The graph represents the total time, T(x), required to complete the round trip, dependent on the average speed on the outgoing trip, x. Which is the correct interpretation of the vertical asymptote x = 100 in the context of this situation? A. The average speed on the outgoing trip could not be less than 100 miles/hour. B. The average speed on the outgoing trip could not be more than 100 miles/hour. C. The total time for the round trip decreases infinitely when the average speed on the outgoing trip is less than 100 miles/hour. D. The total time for the round trip gets closer to zero when the average speed on the outgoing trip increases.

Mathematics

1 answer:

Nezavi [6.7K] · Answer 1 · 2022-07-26T02:58:38+03:00

Nezavi [6.7K]3 years ago

6 0

Answer:

Step-by-step explanation:

[55X+43,810-65X]/3,575=11.14

55X-65X+43,810=11.14*3,575

-10X=39,825.5-43,810

-10X=-3,984.5

X=-3,984.5/-10

X=398.45 MILES IS THE DISTANCE DRIVEN 65 MPH.

674-398.45=275.5 FOR THE 55 MPH DRIVE.

PROOF:

398.45/65+275.5/55=11.14

6.13+5.01=11.14

11.14=11.14