Question

Hey guys please help me out. Math isn't exactly my strong subject and I'd really appreciate this answer with steps. Thank you in advance :)

Answer 1

B1 = 2
b2 = (b1)^2 + 1 = 2^2 + 1 = 5
b3 = (b2)^2 + 1 = 5^2 + 1 = 26

b4 = (b3)^2 + 1 = 26^2 + 1 = 676+1=677

Answer 2

$b_1=2 \ \ \ \\ \\ b_n=(b_{n-1})^2+1$

Find the 4th term....

n = 4

$b_4=(b_{4-1})^2+1 \\ \\ b_4=(b_3)^2+1 \\ \\ b_4=(26)^2+1 \\ \\ b_4=676+1 \\\\ b_4=677\\\\ \\ \\ ================================ \\ \\ We \ need \ to \ find \ the \ 3rd \ term \ of \ the \ sequence \\\\ n=3 \\\\b_3=(b_{3-1})^2+1 \\\\b_3=(b_2)^2+1\\\\b_3=(5)^2+1 \\\\b_3=25+1\\\\b_3=26\\ --------------- \\ b_2=(b_{2-1})^2+1\\\\b_2=(b_1)^2+1\\\\b_2=(2)^2+1\\\\b_2=4+1\\\\b_2=5\\ ============================$