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rjkz [21]
3 years ago
8

Solve four and three fourths minus one and one third.

Mathematics
2 answers:
Greeley [361]3 years ago
5 0

Answer:

c

Step-by-step explanation:

Soloha48 [4]3 years ago
3 0
Answer: c.

Explanation: The first thing you do when you subtract mixed numbers is convert them into improper fractions. 4 3/4 can be converted to 19/4 and 1 1/3 can be converted into 4/3. To be able to subtract or add fractions they need to have the same denominator a number in which both denominators can go into and that number is 12. 4 can equally go into 12 and so can 3. Now that you have found the common denominator (12) you have to find out what kind of operation you need to do in order for 4 to be 12 and for 3 to also be 12. And that is by multiplying. If you multiply 4 by 3 and get 12 and 3 by 4 to get 12 as well. Whatever you do to the bottom of the fraction you also do to the top so 19 x 3 / 4 x 3 = 57/12. Do the same to the other improper fraction: 4 x 4/ 3 x4 = 16/12. They both now have the same denominator but you have to subtract so,,57/12 - 16/12 = 41/12 you have the answer to the subtraction problem but you can probably tell that it isn’t any of the options on the question. Simplifying 41/12 will give you the mixed number 3 5/12.
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5.5 : 30.80 = 7 : x

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3 years ago
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suppose the nightly rate for a three star hotel in paris is thought to be bell-shaped and symmetrical with a mean of 160 euros a
Westkost [7]

Answer:

95.44%

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For any given rate, X, the z-score is:

z=\frac{X-\mu}{\sigma}

For X = 144 euros:

z=\frac{144-160}{8}\\ z=-2

For X= 176 euros

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8 0
4 years ago
For each of the figures, write an absolute value equation to satisfy the given solution set.
Valentin [98]

Answer:

|x-1|=5

Step-by-step explanation:

From the diagram you can see that the solutions of the equation are x_1=-4 and x_2=6

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1/2(-4+6)=1

2. Find the distance between points x=1 and x=6 (or between x=1 and x=-4):

d=6-1=5

3. Writhe an absolute value equation (the distanse from endpoints x_1=-4 and x_2=6 to the midpoint x=1 is equal 5):

|x-1|=5

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