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Neporo4naja [7]
3 years ago
9

Given the equation y=1/2x-2 , determine the value for x when y = 8

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

x=20

Step-by-step explanation:

we have

y=\frac{1}{2}x-2

This is a linear equation (equation of a line)

To determine the value of x when the value of y=8, substitute the value of y in the equation and solve for x

so

For y=8

substitute

8=\frac{1}{2}x-2

isolate the variable x

Adds 2 both sides

8+2=\frac{1}{2}x-2+2

10=\frac{1}{2}x

Multiply by 2 both sides

10*2=(2)\frac{1}{2}x

Rewrite

x=20

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Peter walked 10m from X to Y on bearing 020° and then he turned and walked 20m to Z with bearing 140° of Z from Y. Find the dist
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Answer:

17.32m ; 110°

Step-by-step explanation:

Distance between X and Z

To calculate the distance between X and Z

y^2 = x^2 + z^2 - (2xz)*cosY

x = 20, Z = 10

y^2 = 20^2 + 10^2 - (2*20*10)* cos60°

y^2 = 400 + 100 - (400)* 0.5

y^2 = 500 - 200

y^2 = 300

y = sqrt(300)

y = 17.32m

Bearing of Z from X:

Using cosine rule :

Cos X = (y^2 + z^2 - x^2) / 2yz

Cos X = (300 + 100 - 400) / (2 * 20 '*10)

Cos X = 0 / 400

Cos X = 0

X = cos^-1 (0)

X = 90°

Bearing of Z from X

= 20° + X

= 20° + 90°

= 110°

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3 years ago
Simplify <br> 1+tan^2 x / tan^2 x <br> a) sin^2 x <br> b) csc^2 x<br> c) sec^2 x <br> d) cos^2 x
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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