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kirill [66]
3 years ago
9

How do you find the variable z in the problem?

Mathematics
1 answer:
IgorC [24]3 years ago
3 0
Check the picture below

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How to find the distance between two pairs of points
Andre45 [30]
The distance formula<span> is derived from the Pythagorean theorem. To </span>find the distance between two points<span> (x</span>1,y1) and (x2,y2<span>).
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3 0
3 years ago
What does the slope and the intercept mean in -3x +4y = 18
Scorpion4ik [409]
I don’t know just need points
5 0
3 years ago
1. The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75
ryzh [129]
If this were to be graphed, the independent variable would be the price of the ticket for the rides. The dependent variable would be the total cost.

The fair admission is not a variable because it is a constant price for every single person who goes into the fair.

The problem asks to use y to represent the total cost and x to represent the number of ride tickets. In order to fully write out the equation, we have to figure out what the fair admission costs.

43.75 = 1.25(25) + b

*b represents the fair admission

Multiply 1.25 by 25

43.75 = 31.25 + b

Subtract 31.25 to find what b costs.

12.50 = b

The fair admission costs $12.50.

Solution: y = 1.25x + 12.50

3 0
2 years ago
Read 2 more answers
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
Complete. Express the product in simplest form.<br><br> 2/5 of 7/10 =
tester [92]
Of means multiply in math (most of the time). 
So multiply. 
2/5 x 7/10 = 14/50 divided by 2/2 = 7/25 
3 0
3 years ago
Read 2 more answers
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