t = 2 → A true
given I = PRT
to find T , divide both sides by PR
note that R = 6% = 
= 0.06
T = 
= 42/( 350 × 0.06 ) = 2
Answer with Step-by-step explanation:
We are given that displacement of wave
Where y in cm and t in sec.
a.Compare it with
Amplitude of wave=A
We get A=1.5
Amplitude=A=1.5 cm
b.k=0.68
Using 
Wavelength of the wave=9.2 cm
c.Period=
The period of the wave=0.17 s
Speed of the wave=
Speed of the wave=54.1 cm/s
Answer:
Blank 1: 64° (or 32°, depending on what the label applies to)
Blank 2: 42
Step-by-step explanation:
It is a common mistake to believe you have solved the problem when you have found the value of the variable(s) in the problem. You have correctly found the values of n (42) and m (9). However, that is not what the problem is asking for.
We cannot tell if the value (1/2n+11)° is referring to angle DAB, or to angle CAB. In any event, (1/2n+11)° = (1/2×42 +11)° = 32°.
If that is angle CAB, then angle DAB is twice that value, 64°.
If that is angle DAB, then angle DAB is 32°.
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The side length CD is the same as any other side length in a rhombus, so ...
CD = 4m+6 = 4×9 +6
CD = 42 . . . . units
The Correct answer is 3
Explanation:
Using the defined function, f(a) will produce the same result when substituted for x:
F(x)=x^2-x^3
Setting this equal to 4, you can solve for a:
a2 – 5 = 4
a2 = 9
a = –3 or 3
Step-by-step explanation:
A=p(1+r/100)ⁿ
6000=p(1+0.04)¹⁰
6000/(1.04)¹⁰=p
p=6000/1.48
p=4054.05
I would appreciate if my answer is chosen as a brainliest answer
