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Strike441 [17]
3 years ago
14

Which of the following inverse functions are defined for x=-1/2? Select all thst apply.

Mathematics
2 answers:
daser333 [38]3 years ago
4 0
All but the last one I think but don't quote me
ludmilkaskok [199]3 years ago
3 0

Solution:

Function      Domain

sin−1(x)            [−1,1]   →→→→→Defined

cos−1(x)           [−1,1]  →→→→→Defined

tan−1(x)          (−∞,∞)  →→→→→Defined

cot−1(x)          (−∞,∞)  →→→→→Defined

sec−1(x)        (−∞,−1]∪[1,∞)  →→→→→ not Defined

cosec−1(x)     (−∞,−1]∪[1,∞)  →→→→→not Defined

As, you can see that, all inverse trigonometric functions are defined for, x=\frac{-1}{2}, except sec−1(x)   and cosec−1(x)

, whose domain is not valid or do not exist when , x=\frac{-1}{2}.

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What value of $k$ will make $4x^2 - 20x + k$ the square of a binomial?
Arisa [49]

Answer:

k = 25

Step-by-step explanation:

(2x  - sqrt(k) )^2              Expand this as a binomial                          

4x^2 - 4x*sqrt(k) + k      The middle term must be -20x Solve for k so it is

-4xsqrt(k) = - 20x            Divide by -4x

sqrt(k) = -20x/-4x             Do the division

sqrt(k) = 5                         Square both sides

k = 25


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Question 13
Rasek [7]

Answer:

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Step-by-step explanation:

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2 years ago
(10v^4 + 30v^3 + 2v^2) / 10v
Zina [86]

Given expression is

\frac{10v^4+30v^3+2v^2}{10v}

Now we need to simplify this expression. We can begin by factoring numerator and denominator if possible.

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divide numerator and denominator both by 2v

= \frac{v(5v^2+15v+1)}{5}

= \frac{5v^3+15v^2+1v}{5}

Hence final answer is \frac{5v^3+15v^2+1v}{5}

Or you can also keep factored form

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y = -1/4x - 1.

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y = 4x + 5

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y + 1 = -1/4x

y = -1/4x - 1.

7 0
2 years ago
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