Ask question

Ask question

All categories

3 years ago

14

Use a normal approximation to find the probability of the indicated number of voters. In this case assume that 150 eligible vote

rs aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.
The probability that fewer than 39 of 150 eligible voters voted is

1 answer:

alexdok [17]3 years ago

8 0

The number of people who voted follows a binomial distribution with probability of having voted $p=0.22$ and $n=150$ subjects, which means the approximating normal distribution should have mean $np=33$ and standard deviation $\sqrt{np(1-p)}\approx5.07$ .

With the continuity correction, you have

$\mathbb P(X$

You might be interested in

The width of a box in the shape of a rectangular prism is 4 inches more than the height h . The length is the difference of 9 in

Doss [256]

Answer:

$(a)$ $V = -H^3+ 5H^2 + 36H$

$(b)$ $Length = 5in; Width = 9in; Height = 5in$ or $Length = 3in; Width = 10in; Height = 6in$

Step-by-step explanation:

Let:

$W=Width; L = Length; H = Height$

Given

$W = 4 + H$

$L = 9 - H$

Solving (a): The polynomial for the volume in terms of height

Volume (V) is calculated using:

$V = L * W * H$

$V = (9 - H) * (4 + H) * H$

Expand

$V = (9 - H) * (4H + H^2)$

Open brackets

$V = 36H + 9H^2 - 4H^2 - H^3$

$V = 36H + 5H^2 - H^3$

Rewrite as:

$V = -H^3+ 5H^2 + 36H$

Solving (b): The dimensions when Volume = 180

Substitute 180 for V in: $V = -H^3+ 5H^2 + 36H$

$180 = -H^3+ 5H^2 + 36H$

Rewrite as:

$H^3 - 5H^2 - 36H + 180 = 0$

Factorize:

$H^2(H - 5) - 36(H - 5) = 0$

$(H^2 - 36)(H - 5) = 0$

Express $H^2 - 36$ as difference of two squares

$(H - 6)(H + 6)(H - 5) =0$

This gives:

$H - 6 =0==> H = 6$

$H + 6 =0==> H = -6$

$H - 5 =0==> H = 5$

Since the height can not be negative, then H = 5 or H = 6

Recall that:

$W = 4 + H$

$L = 9 - H$

When H = 5

$W = 4 + 5 = 9$

$L = 9 - 5 = 4$

When H = 6

$W = 4 + 6 = 10$

$L = 9 - 6 = 3$

Hence, the dimensions of the box are:

$Length = 5in; Width = 9in; Height = 5in$

or

$Length = 3in; Width = 10in; Height = 6in$

3 0

3 years ago

Answer, please. I need help.

Illusion [34]

Answer: I don't believe it is possible to evaluate the expression.

Step-by-step explanation:

According to an algebra calculator, there is no way to evaluate it because there is no variable. Hopefully this helps?

5 0

4 years ago

Read 2 more answers

Create an equation to represent the total amount of money Matt and Phil earned at the fundraiser based on the number of cookies

bazaltina [42]

Answer:

A = (0.25)(0.8)(x + 1.25x)

Step-by-step explanation:

Let x = number of cookies Matt made

Let 1.25x = number of cookies Phil made {Phil made 25% more cookies than Matt}

A = total money earned

A = (0.25)(0.8)(x + 1.25x)

They sold 80% of the combined cookies made at $0.25 each.

4 0

4 years ago

HELPPPPPPPPP i have the most trouble with math what’s the answer??

weqwewe [10]

Answer: Third option

Step-by-step explanation:

Remember that:

$\sqrt[n]{x^n}=x$

And the Product of powers property:

$(a^m)(a^n)=a^{(m+n)}$

The expression is:

$\sqrt[4]{\frac{3}{2x}}$

To simplify this expression, you need to multiply the denominator and the numerator by $2^3x^3$ . Then:

$\frac{\sqrt[4]{3}}{\sqrt[4]{2x}}=\frac{\sqrt[4]{3(2^3x^3)}}{\sqrt[4]{2x(2^3x^3)}}$

Simplifiying, you get:

$\frac{\sqrt[4]{3(8x^3)}}{\sqrt[4]{2x(2^3x^3)}}=\frac{\sqrt[4]{24x^3}}{\sqrt[4]{2^4x^4}}=\frac{\sqrt[4]{24x^3}}{2x}$

7 0

4 years ago

In circle V, a diameter and one chord intersect at point W. Find tha value of x. A. 4.9 B. 6.3 C. 8 D. 20

solmaris [256]

V - the center of a circle;
r = 10
In the triangle VWS :
WS = x
VS = 10 ( hypotenuse )
VW = 10 - 4 = 6
We will use the Pythagorean theorem:
x² + 6² = 10²
x² + 36 = 100
x² = 100 - 36
x² = 64
x = √ 64 = 8
Answer:
C ) 8

6 0

4 years ago