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alexandr402 [8]
2 years ago
15

PROBLEM 2 What is the greatest common factor of 15 and 30?

Mathematics
2 answers:
seropon [69]2 years ago
7 0

Answer: 15

Step-by-step explanation:

Liono4ka [1.6K]2 years ago
4 0

Answer:

15 = 3 \times 5 \\ 30 = 3 \times 5 \times 2 \\  \\  \:  \:  \:  \:  \:  \:  \:  = 3 \times 5 \\ \:  \:  \:  \:  \:  \:  \:   = 15

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A vehicle travels 57 kilometers north and then travels 26 kilometers south. What is the current position of the vehicle? (2 poin
solniwko [45]

Answer:

C. 31 kilometers north of its starting location

Step-by-step explanation:

<em>Please see attached a rough sketch of the situation for your reference</em>.

Step one:

Displacement North= 57km

Displacement South= 26km

Required

The  final displacement

The current position is attained by subtracting 26km from 57km

=57-26= 31km

Therefore the current position is

C. 31 kilometers north of its starting location

5 0
2 years ago
First to answer well get brainliest!..<br> Plz
marta [7]
<h2>Answer: It is on the origin or quadrant I</h2>
3 0
3 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x &gt; 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
PLZZZ ANSWER!! Answers for points will be reported.
Lisa [10]

Answer:

  • 272.6

Step-by-step explanation:

This is an isosceles triangle with base of 21 and sides of 28.

<u>Area formula</u>

  • A = 1/2bh

<u>Find height:</u>

  • h = \sqrt{28^2 - (21/2)^2}  = \sqrt{673.75} = 25.96

<u>Area:</u>

  • A = 1/2(25.96)(21) = 272.6 (rounded)
7 0
2 years ago
Which number line shows the solution to the inequality 6x+9 greater than or equal to 3
Charra [1.4K]

Answer:

B

Step-by-step explanation:

7 0
2 years ago
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