Question

PLEASE HELP!!!!! For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work.
y = -2x^2 + 2x +2

Answer 1

We are given this equation

$y=-2x^{2} +2x+2$

The vertex form is given by:

$y=a(x-h)^{2} +k$

Now let us try to convert our equation into vertex form:

$y=-2x^{2} +2x+2$

Vertex form is given by:

$y=-2(x-0.5)^{2} +2.5$

comparing our equation with vertex form ,

The vertex (h,k) is (0.5, 2.5)

Next we have to find y when x=6, plugging x as 6 in the given equation,

$y=-2(6)^{2} +2(6)+2$

y=-58

So at x=6, y=-58.

Answer 2

Vertex = (1/2,5/2) x= 1 + or - square root of 5-2y all over 2