To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer: The equation is W^2 + 4W - 96= 0
{Please note that ^2 means raised to the power of 2}
Step-by-step explanation: We have been given hints as to the measurement of the length and width of the rectangle. The length is given as four more than the width. What that means is that whatever is the width, we simply add four to get the measurement of the length. Therefore if the width is W, then the length is W + 4.
That is,
L = W + 4 and
W = W
Also we have the area given as 96.
Remember that the area of a rectangle is given as
Area = L x W.
In this question, the Area is expressed as
Area = (W + 4) x W
96 = W^2 + 4W
Subtract 96 from both sides of the equation and we have
W^2 + 4W - 96 = 0.
We now have a quadratic equation from which we can determine the dimensions of the rectangle
Answer: 11, 7
11 + 7 = 18
11 x 7 = 77
Answer:
Let the larger number = y and the smaller number = x.
The largest number is 10 less than twice the smaller number. Remember that less than means subtract the 10 from the other amount while twice means multiply by two. Therefore,
y = 2x - 10
The sum of the two numbers is 38. Remember sum means add the two numbers to get their result. Therefore,
x + y = 38
Since y = 2x - 10, we rewrite the lower equation as:
x + (2x - 10) = 38
Solving:
3x - 10 = 38
3x = 48
x = 16
The lesser number is 16 and the greater number is 2(16) - 10 or 22.
