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3 years ago

How many solutions does the following system of equations have?

Mathematics

1 answer:

fgiga [73]3 years ago

3 0

Answer:

This system has one solution only

Step-by-step explanation:

We have to evaluate the equations shown in the picture you gave

Since the equations differs, they are not the same, this system has only on solution for x and for y.

In fact, if we sum them, we obtain y=0, and then x=2

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A cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. If the basin is completely filled with water, how muc

jarptica [38.1K]

Answer:

$39.3 ft^3$

Step-by-step explanation:

The cylindrical basin has a height of 2 ft and a diameter of 5 ft.

To find the amount of water that will completely fill up the basin, we simply need to find the volume of the basin.

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius of the basin (half the diameter) = 2.5 ft

h = height of the basin

Hence, the volume is:

$V = \pi * 2.5^2 * 2$

$V = 39.27 ft^3$ ≅ $39.3 ft^3$

The cylindrical basin can hold up to $39.3 ft^3$ of water.

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The missing number to the letter N is 8

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4 years ago

There are 32 students in the class. Of the class 3/8 of the students bring their own lunch. How many students bring their own lu

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3 years ago

A boy is 3 years more than twice as old as his sister. His sister is 6 years old. How old is the boy?

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Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted

Misha Larkins [42]

Answer:

$\frac{15}{28}$ is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red $= 3 + 5 = 8$

Probability of getting blue $= \frac{3}{8}$

Probability of not getting a blue $=\frac{5}{8}$

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

<u>First Draw Blue, Second Draw Not Blue:</u>

1st Draw: $P(Blue) = \frac{3}{8}$

2nd Draw: $P(Not\:Blue)=\frac{5}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}$

<u>First Draw Not Blue, Second Draw Not Blue:</u>

1st Draw: $P(Not\:Blue)=\frac{5}{8}$

2nd Draw: $P(Not\:Blue)=\frac{3}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}$

To get the probability of exactly one blue, we add both of the events:

$\frac{15}{56}+\frac{15}{56}=\frac{15}{28}$

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3 years ago