1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlada-n [284]
3 years ago
15

A boy is 3 years more than twice as old as his sister. His sister is 6 years old. How old is the boy?

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0
What u do is, take the sister's age, then multiply it by 2 because the boy is 3 years older than TWICE his sister's age. His sister is 6, so 6x2=12, and he is 3 years older, so 6x2+3=15
AlexFokin [52]3 years ago
3 0
The boy is 15 because twice the age of his sister is 12, then you add the three years to it and get 15
You might be interested in
Maritza is buying wheels for her skateboard shop. She ordered a total of 92 wheels. If wheels come in packages of 4, how many pa
poizon [28]
92/4=23

...........................
4 0
4 years ago
Read 2 more answers
Mole Conversion:<br> What is the mass of 3.13 x 1023 molecules of carbon dioxide?
4vir4ik [10]

Answer:

The mass of 3.13*10²³ molecules of carbon dioxide is 22.88 g.

Step-by-step explanation:

Avogadro's Number or Avogadro's Constant is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ molecules are present in 1 mole, 3.13*10²³ molecules are present in how many moles?

moles=\frac{3.13*10^{23}molecules*1 mole }{6.023*10^{23}molecules}

moles= 0.52

Since the molar mass of carbon dioxide is 44 g / mole, then the following rule of three can be applied: if there are 44 g in 1 mole, how much mass is there in 0.52 moles?

mass=\frac{0.52 moles*44 g}{1 mole}

mass= 22.88 g

<u><em>The mass of 3.13*10²³ molecules of carbon dioxide is 22.88 g.</em></u>

8 0
3 years ago
The temperature, t, in Burrtown starts at 21°F at midnight, when h = 0. For the next few hours, the temperature drops 4 degrees
sweet-ann [11.9K]
In this case the temperature depends on the hour.  So temperature is your X and hour is your Y variable.  When h=0, x=0.   So the 21*C is you x=0 or y-int point.  

If we are trying to match the equation for a line of y=mx+b, 21*C=b.  

Our rate of change is -4*C/h, which is our m variable.

So y=(-4)x+(21)

OR in this case, t=-4h+21.

Answer D.
6 0
3 years ago
Read 2 more answers
Why do student need to know the basic of geometric figures in geometry<br> ?
butalik [34]
You use it during your life spand
5 0
3 years ago
Hewo everyone trying to help my brother with his work plzz help
Allisa [31]

Answer:

qpwoeirutyslaksjdhfgzmxncbv

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • during the month of april, dora kept track of the bugs she saw in her garden. She saw a ladybug on 23 days of the month. what is
    6·2 answers
  • Solve fot z show all your work. 7z - 18 =2z+ 18​
    7·1 answer
  • (This was in my adding integers quiz) Lisa owes the bank $60. She gets $85 for her birthday and deposits it into her account. Ho
    7·2 answers
  • Each cupcake costs $4.00 how many cupcakes (x) are purchased if the total cost is $36.00
    11·2 answers
  • What is the value of (4^3)(4^-1)(5^-2)/(4^4)(5^-3)(5^0)
    8·1 answer
  • Rs 600 will gave Rs 90 simple interest at 5 % per annum. ​
    7·1 answer
  • Help me please,it is just regular 5th grade science
    12·2 answers
  • onsider the vectors a→=3i→+j→−k→,b→=−3i→−j→+k→,c→=i→+0.333333j→+0.333333k→ d→=i→+3j→+4k→,g→=i→+3j→−k→. Which pairs (if any) of t
    8·1 answer
  • I need help please and thank you and show work
    7·1 answer
  • In a history class, 30 students were asked about other courses that they were enrolled in: 20 said they were taking math, 22 wer
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!