Answer: Pyramid A: Base is rectangle with length of 10 meters and width of 20 meters.
Pyramid B: Base is square with 10 meter sides.
Heights are the same.
Step-by-step explanation: The volume of pyramid A is TWICE the volume of pyramid B.
If the height of pyramid B increases to twice the of pyramid A, (from 10m to 20m),
V of square pyramid = (10m)² * (10*2)/3 = 100m² * 20m/3 = 100m² * 6.67m = 666.67 m³
The new volume of pyramid B is EQUAL to the volume of pyramid A.
3x2 -8x +4
there are multiple answers to this
To find the area of a rectangle, do length times width. Because we know the length (90 in), we can divide 380 by 90 to find the maximum possible width. This is possible because of the equation width = Area/length, which is derived from width * length = Area. 380/90 = 4.222, so the maximum width to the nearest possible inch is 4 inches.
I'll assume the question is: what's the volume?
It's two L×W×H rectangular prisms (aka boxes) put together
The bottom one is 2×3×4
The top one is 5×4×1
Volume = 2×3×4 + 5×4×1 = 24 + 20 = 44
Answer: 44 cubic feet