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MakcuM [25]
2 years ago
5

Type the equation for the graph below.

Mathematics
1 answer:
trasher [3.6K]2 years ago
5 0

Answer:

<u>y</u><u>=</u><u>log</u><u>(</u><u>pi</u><u> </u><u>divide</u><u> </u><u>by</u><u> </u><u>2</u><u>)</u><u>exponent</u><u> </u><u>×</u>

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Solve the system of linear equations below. 4x - 3y = 17 5x + 4y = 60
LenaWriter [7]
4x-3y=17......(1)
5x+4y=60......(2)

Multiply equation (1) by 4 and equation (2) by 3:-

16x - 12y = 68
15x + 12y = 180

Adding these 2 equations:_

31x = 248
x = 248/31 = 8

Now substitute x = 8 in equation (1):-

4(8) - 3y = 17
32-3y = 17
-3y = -15
y = -15/-3 = 5

So solution is x=8,y=5
5 0
3 years ago
What is 1/2 divided by 4?
Natasha_Volkova [10]
1/2/4=1/2 x 1/4 = 1/8
8 0
3 years ago
Read 2 more answers
Hello please help with my question, I will give brainlyest!
lilavasa [31]

No, John is incorrect.

<h3>Correct work shown:</h3>

\sf x^2 - 6x - 7 = 0

\sf x^2 - 6x = 7

\sf x^2 - 6x  + 9= 7 + 9

\sf (x-3)^2= 16

\sf x-3=\pm \sqrt{16}

\sf x-3= \pm 4

\sf x= + 4 + 3 \quad or \quad x = -4 + 3

\sf x= 7 \quad or \quad x = -1

The correct answer should be x = 7 or x = -1

3 0
2 years ago
Part 1
andreev551 [17]

Answer:

see explanation

Step-by-step explanation:

Part 1

The n th term of a geometric sequence is

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Given a_{6} = 128, then

a(2)^{5} = 128, that is

32a = 128 ( divide both sides by 32 )

a = 4 ← first term

Part 2

a_{21} = 4(2)^{20} = 4 × 1048576 = 4194304

6 0
3 years ago
What is 10 divided by 2/3
netineya [11]
10/2=5
10/3=3.33.....
8 0
3 years ago
Read 2 more answers
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