D = adult
c = child
t = total admission cost
t = 8d + 5c
t = 8(2) + 5(3) = $31
Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
Assuming an uniform distribution, the standard deviation is given by:

In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size is found solving for n when the margin of error is of M = 0.006, hence:





n = 142,282.
A sample of 142,282 should be taken, which is not practical as it is too large of a sample.
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
I believe C because 1840+14%x2which would be the two years = 2355.20
ADC should measure to 115 degrees if both measurements are equal to 180 degrees.
If not, ADC might be 25 degrees if both measurements are equal to 90 degrees.
Hope this helps.
Answer:
so y.u on it lollllll
Step-by-step explanation:
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