Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Answer:
YES
Step-by-step explanation:
So how you can figure this out is you do the Distributive Property.
So it will be 12x^3+12y^2+6y^2+6.
The next thing you have to do is add together the ones that are similar which is 12y^2+6y^2 to get 18y^2.
Your answer is 12x^3+18y^2+6. So YES it can be factored into that form.
A SCATTER PLOT IS JUST A DOT PLOT
Answer:
2x-4 would be the expression simplified.
Step-by-step explanation:
5(x-2) = 5x-10
-3x(x-2) = -3x +6
Combine them by addition 5x-10+-3x+6
2x-4