What needs to be done first is to add up females and males that have passed.
42 + 14 = 56
so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75
out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
NOW WE ARE DOING FAILS.
15 + 5 = 20
so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75
out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
i hope this helped! :)
Answer:
the answer is 5
Step-by-step explanation:
f(4) = 3(4) -2
7 - 2 = 5
Answer:

Step-by-step explanation:

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
<em><u>Solution:</u></em>
Given that,

<em><u>We have to substitute eqn 1 in eqn 2</u></em>






Substitute x = 2.1925 in eqn 1
y = 2.1925 + 3
y = 5.1925
Substitute x = -3.1925 in eqn 1
y = -3.1925 + 3
y = -0.1925
Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
19,000
Step-by-step explanation:
round down if the hundred is above 5 than round up one number