All categories

3 years ago

The set of ordered pairs below represents a relation that is a function.

Mathematics

2 answers:

mr_godi [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Allushta [10]3 years ago

3 0

Answer:

B (4,2)

Step-by-step explanation:

This coordinate pair would make the relation not a function because there would be two X values that are the same.

You might be interested in

Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

weeeeeb [17]

note that gradient = $\frac{dy}{dx}$ at x = a

calculate $\frac{dy}{dx}$ for each pair of functions and compare gradient

(a)

$\frac{dy}{dx}$ = 2x and $\frac{dy}{dx}$ = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)

$\frac{dy}{dx}$ = 2x + 3 and $\frac{dy}{dx}$ = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)

$\frac{dy}{dx}$ = 4x + 13 and $\frac{dy}{dx}$ = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)

$\frac{dy}{dx}$ = 6x - 5 and $\frac{dy}{dx}$ = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x = $x^{\frac{1}{2} }$

$\frac{dy}{dx}$ = 1/(2√x) and $\frac{dy}{dx}$ = 2

at x = 9 : gradient = $\frac{1}{6}$ and 2 and 2 > $\frac{1}{6}$

4 0

3 years ago

Pleaseeee helpppp!!!!

ANTONII [103]

Answer:

The easiest way to do this is to reflect Figure I over the Y axis. Then move it up 3 and left 2.

5 0

3 years ago

Read 2 more answers

This is the graph of y = sin(x). Does anyone know the second part?

Alborosie

Answer:

The resulting graph is $y = 5\cdot \sin x$ .

Step-by-step explanation:

The resulting function is of the form:

$y = A\cdot \sin x + k$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$A$ - Amplitude, dimensionless.

$k$ - Midpoint value, dimensionless.

The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: $A > 0$ . According to the graph, the function is bounded between 5 ( $y_{max}$ ) and -5 ( $y_{min}$ ), and the midpoint value ( $k$ ) is 0. The amplitude is determined by the following calculation: