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Genrish500 [490]
3 years ago
6

What is the next fraction in this sequence? Simplify your answer. 9/20, 21/40, 3/5, 27/40.....?

Mathematics
2 answers:
anygoal [31]3 years ago
3 0
So first identy the type of series by looking at the relationship, in this case it is arithmetic!

So we know it adds up by the same thing everytime which is 3/40!

Next number will be...27/40 +3/40= 30/40

Simplify 30/40, divide by 10 both 30 and 40 to get........ 3/4

So next fraction is 3/4

PSYCHO15rus [73]3 years ago
3 0
I believe the next answer is 3/4
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Consider the formula for the slope between two coordinate points, m, shown below. Which of the following equations is equivalent
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Step-by-step explanation:

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Bill Ding plans to build a new hardware store. He buys a rectangular lot that is 50 ft by 200 ft, the 50-ft dimension being alon
enot [183]

Answer:

Length a = 59.62

Width b = 67.09

Cost = $10,734.4

Step-by-step explanation:

Solution:

Let a be the length and b be the width.

Area of the rectangle = a x b

a x b = 4000

Cost of the construction:

Cost = 100a + 80(a + 2b)

Cost = 100a + 80a + 160b

Cost = 180a + 160b     Equation of the Cost of the construction.

Now, we need a and b to calculate the minimum cost required to build a lot.

From the area = a x b

we have,

a x b = 4000

b = 4000/a

Putting this equation into the cost of the construction.

We get:

Cost = 180a + 160 x (4000/a)

Cost = 180a + 640000/a

Differentiating with respect to a, we get

C^{'} = 180 - 640000/a^{2}

Putting C^{'} = 0

180 - 640000/a^{2} = 0

Taking LCM

180a^{2} - 640000 = 0

Solving for a

180a^{2} = 640000

a^{2} = 640000/180

a^{2} = 3555.55

Taking square root

a = 59.62

As we know,

b = 4000/a

putting the minimum value of a  = 59.62

b = 4000/59.62

b = 67.09

So, now we have both the dimensions a and b

Putting the values of a and b we will get the cost of the construction.

Cost = 180a + 160b

Cost = 180(59.62) + 160(67.09)

Cost = $10,734.4

Hence, $10,734.4 will be the minimum cost of the construction for Bill Ding.    

5 0
3 years ago
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