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Irina18 [472]
3 years ago
14

X^3+y^3=3axy find dy/dx

Mathematics
1 answer:
adoni [48]3 years ago
6 0
x^3+y^3=3axy
\dfrac{\mathrm d}{\mathrm dx}\left[x^3+y^3\right]=\dfrac{\mathrm d}{\mathrm dx}[3axy]
3x^2+3y^2\dfrac{\mathrm dy}{\mathrm dx}=3a\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)
\left(3y^2-3ax\right)\dfrac{\mathrm dy}{\mathrm dx}=3ay-3x^2
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3ay-3x^2}{3y^2-3ax}
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{ay-x^2}{y^2-ax}
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Answer:

The expression given by Ivy is WRONG.

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Now, the point scored in the first game  = 38 points

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Step-by-step explanation:

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<em></em>

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or

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55% of 840 is...

<em>462</em>

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<em>Hope this helps! <3</em>

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