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3 years ago

-2m=6 Solve the equation using full working out

Mathematics

1 answer:

storchak [24]3 years ago

7 0

Answer:

m = -3

Step-by-step explanation:

-2m=6

Divide both sides by (-2).

m = 6 ÷ (-2)

m = -3

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4) ASAP P-LZ ANSWER THIS QUESTION AND IT MUST SHOW WORK AND IT MUST BE RIGHT PLZZZZZPLZZZZ

cluponka [151]

Answer:

In 4 months

Step-by-step explanation:

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3 years ago

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Lingjin drove from los angeles to ventura during rush hour at an average speed of 4545 miles per hour, and then drove back the s

Softa [21]

45mph times x hours one way
30mph times y hours back
x+y=3 hours 15 minutes

45mph(x)=z miles
30mph(y)=smiles
so
$45x = 30y \\ x = \frac{30}{45} y \\ x = \frac{2}{3} y$
and substituting we know 15 minutes is 1/4 an hour so we have
$x + y = 3.25 \\ \frac{2}{3} y + y = 3.25 \\ \frac{5}{3} y = \frac{13}{4} \\ y = \frac{13}{4} ( \frac{3}{5} ) \\ y = \frac{39}{20}$
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3 years ago

Please help me with my problem. I would really appreciate it

Karo-lina-s [1.5K]

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3 years ago

Jason plays on the Riverdale Middle

goldfiish [28.3K]

Answer:

Step-by-step explanation:

First find the mean. 20 + 12 + 23 + 8 + 17 + 16 = 96 / 6 = 16

Take the highest number and subtract the mean 23 - 16 = 7

Do the same with the lowest 13 - 8 = 5

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3 years ago

Suppose that any given year, the value of a certain investment is increased by 15%. If the value is now $15,000, in how many yea

Yanka [14]

The answer is 2.5 years.

The compound interest formula is:
A = P(1 + r/n)ⁿˣ
A - the final value
P - the initial value
r - the interest rate
n - the number of times interest is compounded by year
t - the numbers of years of investment

We have:
A = $21,000
P = $15,000
r = 15% = 15/100 = 0.15
n = 1 (since this is per year)
t = ?

So:
$21000 = 15000(1 + 0.15/1) ^{1*t} \\ 21000=15000(1+0.15) ^{t} \\ 21000 = 15000 * 1.15 ^{t} \\ 1.15 ^{t}=21000/15000 \\ 1.15 ^{t}=1.4$

Now, logarithm both sides of the equation:
$log(1.15 ^{t})=log(1.4)$

Since $log (x^{a}) =a*log(x)$ , then $log (1.15^{t}) =t*log(1.15)$
Therefore:
$t*log(1.15)=log(1.4) \\ 
t = \frac{log(1.4)}{log(1.15)} \\ 
t = \frac{0.15}{0.06} \\ 
t = 2.5$

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4 years ago