All categories

3 years ago

I need help with these questions 1-6 true or false

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

6 0

1 is true because if it snows then it is usally around winter time so that means that it is most likeyly cold out.

You might be interested in

Find the 17th term in the sequence for which a1 = 10 and d = -3.

yKpoI14uk [10]

Answer:

d. -38

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is as follows:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

$a_{n} = a_{1} + (n-1)*d$

In this question:

$a_{1} = 10, d = -3$

17th term:

$a_{17} = a_{1} + (17-1)*d = 10 + 16*(-3) = -38$

So the correct answer is:

d. -38

6 0

3 years ago

polygon A i simllar to polgon B. find the perimeer of polygon B if one side of polygon A is 24 A sde to polygon B is 15 and the

Gemiola [76]

Answer:

Perimeter of polygon B = 80 units

Step-by-step explanation:

Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

Let $x$ be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.

Let's replace those value sin our proportion and solve for $x$ :

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

$\frac{24}{15} =\frac{128}{x}$

$x=\frac{128*15}{24}$

$x=\frac{1920}{24}$

$x=80$

We can conclude that the perimeter of polygon B is 80 units.

8 0

3 years ago

43.4 + 63.7 × ( -0.23)

LenKa [72]

Answer:

The answer is 28.749...

3 0

3 years ago

Read 2 more answers

Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.

dalvyx [7]

Answer:

The measure of the side $QR$ is 8.8.

Step-by-step explanation:

Since $LMNO \sim PQRS$ , then $SP \propto OL$ , $RS \propto ON$ , $RQ \propto MN$ and $QP \propto LM$ . From figure we have the following relationship: