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3 years ago

Easy questions pls help (question in picture)

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

6 0

Answer:

1. P= 80

60/.75=80

2. x= 5/3

-27/25x / -27/25= -9/5 / -27/25

-9/5 / -27/25 --- -9/5 x -25/27

3. -300

-2.7/-2.7 = 810/-2.7

4. 120

84x100/70

84/x = 70/100

MAVERICK [17]3 years ago

3 0

1. p=80

=(60×4)÷3

=240÷3

=80

2.x=1.6667

={-9/5}×{-25/27}

=1.6667

3.t=-300

=(810÷-2.7)

=(810×10)÷(-2.7×10)

=(8100÷(-27)

=300

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you can speed from 0 to 25 m/s in 25 seconds and your friend can speed up from 0 to 6 m/s in 6 seconds. who is faster

aksik [14]

Answer:

Neither; see below

Step-by-step explanation:

Your acceleration: $a=\frac{\Delta v}{\Delta t}=\frac{25-0}{25}=1m/s^2$

Your friend's acceleration: $a=\frac{\Delta v}{\Delta t}=\frac{6-0}{6}=1m/s^2$

Therefore, since both you and your friend accelerate at the same rate, neither is faster.

7 0

3 years ago

Dvinal [7]

Answer B

Explanation: Y=mx+b
M=slope and b=yintercept

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3 years ago

Find the surface area of composite figure. use 3.14 for π. round to the nearest tenth

ExtremeBDS [4]

Combining of the two cylinders gives a composite figure that has the surface area of a solid cylinder of radius 7 mm and height 6 mm, such that the surface area of the figure is approximately 571.5 mm².

<h3>Which method can be used to find the surface area of the figure?</h3>

Radius of the inner cylinder, r = 3 mm

Radius of the outer cylinder, R = 7 mm

Height of the cylinders, h = 6 mm

Given that the inner cylinder exactly fits into the outer cylinder, we have;

The surface area of the composite figure is the surface area of the hollow outer cylinder + The area of the top and bottom of the inner cylinder.

Which gives;

The surface area of the composite figure, A, is the surface area of a solid cylinder, using the dimensions of the hollow outer cylinder.

A = 2•π•R² + 2•π•R•h

Which gives;

A = 2 × π × 7² + 2 × π × 7 × 6

Where, π = 3.14, we have;

A = 2 × 3.14 × 7² + 2 × 3.14 × 7 × 6 ≈ 571.5

The surface area of the composite figure, A ≈ 571.5 mm²

Learn more about the analyzing of composite figures here:

brainly.com/question/21135654

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4 0

2 years ago

2. Suppose the temperature that most foods can stay bacteria free in restaurants varies approximately according to a normal dist

vagabundo [1.1K]

Answer:

28.4

Step-by-step explanation:

Given that:

Mean, m = 31.3

Standard deviation, s = 2.8

Since, data is normally distributed :

P(x < 0.15) gives a Z value of - 1.036

Using the Zscore formula :

Z = (x - mean) / standard deviation

-1.036 = (x - 31.3) / 2.8

-1.036 * 2.8 = x - 31.3

-2.9008 = x - 31.3

-2.9008 + 31.3 = x

28.3992 = x

The temperature which correlates to the bottom 15% of the distribution is 28.4

7 0

3 years ago

2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3

ratelena [41]

Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

$x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29$

The associated matrix to the system is

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]$

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]$

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]$

Using backward substitution we have that

$0x_5=-140$ , then $0=-140$ and this is absurd. Then The system is inconsistent.

4 0

4 years ago