the base of a triangle is 8 inches more than the height. The area is 45 inches. Find the dimensions of the triangle
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This is a question that will require Pythagoras' theorem as you want to find the length of a diagonal of a triangle and are given the measurements of two sides. I have attached a picture of how to solve this problem.
To the nearest 10th of a foot, the answer is 77.6ft
To the nearest 10th of a foot, the answer is 77.6ft