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Harman [31]
3 years ago
14

Easy question!!

Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0

Answer: 1+log3(10)

Step-by-step explanation:

Lelu [443]3 years ago
8 0

Answer:

6

Step-by-step explanation:

\log _3\left(27\right)+\log _2\left(8\right)\\\log _3\left(27\right)=3\\\log _3\left(27\right)\\\mathrm{Rewrite\:}27\mathrm{\:in\:power-base\:form:}\quad 27=3^3\\=\log _3\left(3^3\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\\\log _3\left(3^3\right)=3\log _3\left(3\right)\\=3\log _3\left(3\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\log _3\left(3\right)=1\\=3\cdot \:1\\\mathrm{Multiply\:the\:numbers:}\:3\cdot \:1=3\\=3

\log _2\left(8\right)=3\\\log _2\left(8\right)\\\mathrm{Rewrite\:}8\mathrm{\:in\:power-base\:form:}\quad 8=2^3\\=\log _2\left(2^3\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\\\log _2\left(2^3\right)=3\log _2\left(2\right)\\=3\log _2\left(2\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\log _2\left(2\right)=1\\=3\cdot \:1\\\mathrm{Multiply\:the\:numbers:}\:3\cdot \:1=\\=3\\=3+3\\Simplify\\=6

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